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Accessing node namespace in code assigned by roslaunch

asked 2022-09-07 09:26:33 -0500

JaFeKl
26 ●4 ●7 ●8

updated 2023-06-18 10:05:39 -0500

lucasw

8729 ●137 ●239 ●256 https://github.com/lucasw

Hello everyone,

I have the following problem. I am running a node from a launch file based on a group ns.

<launch>  
 <group ns = "transferunit_1">  
<node name="transferunit1_hardware", pkg="transferunit_hardware"/>  
</group>  
</launch>

This makes the node correctly be started in the namespace. /transferunit_1/transferunit_hardware

In the .cpp file of the node I'am currently doing the following:

ros::init(argc, argv, "transferunit_hardware");  
std::string ns = ros::thisnode::getNamespace();

However, ns is just empty "/" ....

How can I access the namespace that has been assigned during roslaunch?

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answered 2022-09-07 16:55:34 -0500

Mike Scheutzow
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I don't recognize the ros::thisnode syntax you used, there are 0 hits for it in google search, and it doesn't compile on my machine. This is the standard way to obtain the current namespace:

ros::init(argc, argv, "my_ros_node");
ros::NodeHandle nh;
std::string ns = nh.getNamespace();

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This might be a typo.

ros::this_node does exist, and contains a class ThisNode which does have a method getNameSpace(). See the documentation. The same method exists as a free function in the ros::this_node namespace (see here).

gvdhoorn ( 2022-09-08 02:34:09 -0500 )edit

ros::thisnode::getNamespace();

@gvdhoorn More like 3 typos! Thanks for the information, I haven't seen that class before.

Mike Scheutzow ( 2022-09-08 06:33:14 -0500 )edit

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Asked: 2022-09-07 09:26:33 -0500

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Last updated: Sep 07 '22

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