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Programmatically get node's Namespace

asked 2013-05-13 06:48:25 -0600

Claudio

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updated 2017-07-11 08:40:00 -0600

lucasw

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Is there a way to get a node's current namespace?

Say I launch a node like this

<launch>
<group ns="robot_1">
<node pkg="myrobot" type="robot" name="robot"/>
</group>
</launch>

then this node is really called /robot_1/robot. Now what if it should publish something on a topic whose name depends on the namespace?

So in this case the topic may be /robot_1/control.

Is there a way I can get my code to dynamically find this namespace?

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Do you mean that you'd prefer to select that the node publishes in /robot_1/robot instead of /robot?

SL Remy ( 2013-05-13 06:54:31 -0600 )edit

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answered 2013-05-13 10:54:41 -0600

jarvisschultz

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updated 2021-06-11 08:19:06 -0600

130s

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If something needs to subscribe to the control topic, if it is in the same namespace as the robot node then subscribing to control will automatically find the /robot_1/control topic. Subscribing to /control will not automatically find the one you want. More can be read here.

Also note that if for some reason you need to get the namespace of a particular node from within that node you can do this in both roscpp and rospy using

std::string ns = ros::this_node::getNamespace();

and

ns = rospy.get_namespace()

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Thanks Jarvis, that was exactly what I needed.

Claudio ( 2013-05-13 20:53:43 -0600 )edit

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Asked: 2013-05-13 06:48:25 -0600

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Last updated: Jun 11 '21

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