**Answer:**

The flowering population is in Hardy Weinberg equilibrium.

**Step by Step Explanation:**

Total initial population size = 60

As both the populations are homozygous so the frequency of alleles will be,

P = 80/120= 0.66

q = 40/120= 0.33

The predicted frequencies for genotypes once the population has reached Hardy-Weinberg

p2 = 0.4356

2pq= 0.4356

q2 = 0.1089

The number of plants with each type of flower in a papulation of 420 is,

Homozygous dominant= 185

heterozygous= 185

Homozygous recessive= 50

**Chi square analysis:**

The observed values for red-flowered plants, pink-flowered plants, and white-flowered plants are not significantly different from the expected values predicted by Hardy Weinberg equilibrium.

Phenotype observed(o) expected (e) (o-e)2/e

Red 178 185 0.26

Pink 190 185 0.135

White 52 50 0.08

chi-square = 0.474

With 2 degree of freedom this chi-square gives a p value of 0.7 - 0.8, which is not significant.