Ask Your Question
0

xacro: parametrable constants?

asked 2013-09-29 09:44:56 -0500

Arn-O gravatar image

updated 2013-09-29 09:45:23 -0500

Hi.

I'm working on a robotic arm and I have this code block 5 times in my urdf file:

  <!-- arm_1 link -->
<link name="arm_1_link">
  <inertial>
    <mass value="${arm_1_link_mass}" />
    <inertia ixx="0.010" ixy="0.000" ixz="0.000" iyy="0.010" iyz="0.000" izz="0.010" />
  </inertial>

  <visual>
    <geometry> 
      <mesh filename="package://youbot_description/meshes/arm_joint_1.dae"/>
    </geometry> 
  </visual>
</link>

  <!-- arm_1 joint -->
    <joint name="arm_1_joint" type="revolute">
      <origin xyz="${arm_1_link_pose_x} ${arm_1_link_pose_y} ${arm_1_link_pose_z}" 
              rpy="${arm_1_link_orient_r} ${arm_1_link_orient_p} ${arm_1_link_orient_y}" />
      <parent link="arm_base_link"/>
      <child link="arm_1_link" />
      <axis xyz="${arm_1_axis}" />
      <limit lower="${arm_1_limit_min}" upper="${arm_1_limit_max}"
             effort="${arm_joint_effort}" velocity="${arm_joint_velocity}" />
    </joint>

I would like to use a smart macro to only have one block called 5 times. I would ideally only use the joint number as a parameter. The values are stored on another file in xacro:property.

The issue: how to transform this ${arm_1_limit_min} with a parameter? ${arm_${param_name}_limit_min} does not work.

Thanks for your answers!

edit retag flag offensive close merge delete

2 Answers

Sort by » oldest newest most voted
0

answered 2013-10-01 11:32:55 -0500

Arn-O gravatar image

I guess I was tired when I raise this question.

The solution is to create one macro for the inertia and mass and another one for the origin, parent, origin and axis of the joint. The macros can be called dynamically with a single parameter.

The specific arm part values have to be stored in the macros directly.

That gives a very readable code, with 5 calls to a macro, calling sub-macros. And a set of five macros very close to the spec sheet of the arm parts.

edit flag offensive delete link more

Comments

Hi, could you provide some example of your solution? I've tried using a macro that receives property id, and builds up property name while passing it as parameter to another macro. Unfortunately, it seems that the nested macro treats that param as a string and does not resolve it to a property.

jolesinski gravatar imagejolesinski ( 2015-12-30 04:45:59 -0500 )edit

Well, this question is a bit old, but you can look at this repo:

https://github.com/Arn-O/youbot_ros_t...

Arn-O gravatar imageArn-O ( 2015-12-30 16:36:39 -0500 )edit

Thanks for help. I see that u extracted inertias and joints to macros in separate file. This makes the code more readable, but it still requires copy-pasting of all the arm_id stuff and modifying the ids everywhere manually. Not exactly what I was looking for, but it seems that theres no better way.

jolesinski gravatar imagejolesinski ( 2016-01-04 12:30:46 -0500 )edit

One more question, do you recall what you meant by "The macros can be called dynamically with a single parameter." ? I don't see it in your repo, but calling a macro by dynamic names would be a solution. I see it in jade possible by xacro:call, unfortunatelly Im bound to previous releases

jolesinski gravatar imagejolesinski ( 2016-01-04 13:00:34 -0500 )edit

Correct, it is not that "dynamic". My assumption is that you cannot make it dynamic, since it is designed for robot description, and robot description are supposed to be "static". Not nice for coders, but XML is not really a programming language, just a markup language.

Arn-O gravatar imageArn-O ( 2016-01-05 09:36:31 -0500 )edit
0

answered 2013-09-30 02:24:41 -0500

updated 2013-09-30 02:29:23 -0500

I think this should be able to do what you want. Xacro offers parameterized macros (specifically the "params" attribute in the macro definition):

http://wiki.ros.org/urdf/Tutorials/Using%20Xacro%20to%20Clean%20Up%20a%20URDF%20File#Parameterized_Macro

<xacro:macro name="blue_shape" params="name">
           <link name="${name}">
               ....

I think the parameter functionality with simple concatenation (in the constants section http://wiki.ros.org/urdf/Tutorials/Using%20Xacro%20to%20Clean%20Up%20a%20URDF%20File#Constants):

<link name=”${robotname}s_leg” />
edit flag offensive delete link more

Comments

Thx for your answer. I know how to define a parameter ... the issue is that I need to define a property that should be based on the parameter. Let's say that you have a param "name", I need to use the name in a property. So it should be something like {$property_${name}} but that does not work.

Arn-O gravatar imageArn-O ( 2013-09-30 09:14:42 -0500 )edit

Oh. I'm sorry, I didn't fully understand what you were asking until just now. I don't know how to do something like that. I would suggest passing in all the parameters to the macro instead of trying to construct them internally. Probably not the answer you wanted though.

skiesel gravatar imageskiesel ( 2013-09-30 09:22:12 -0500 )edit

Thanks anyway for the time spent on it. I don't think we can do it easily. Passing all the parameters gives a pretty ugly code. An option would be to define block macro for the origin, limits, etc. and using the param to dynamically call those macros. Still have to code 5 times the blocks.

Arn-O gravatar imageArn-O ( 2013-09-30 09:28:33 -0500 )edit

Your Answer

Please start posting anonymously - your entry will be published after you log in or create a new account.

Add Answer

Question Tools

1 follower

Stats

Asked: 2013-09-29 09:44:56 -0500

Seen: 358 times

Last updated: Oct 01 '13