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rospy publisher and subscriber in the same node, filter out "own" messages

publisher+subscriber

asked 2016-04-11 10:24:48 -0600

peci1

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Hey ROS folks

I have a node in Python, in which I subscribe to a topic, and I also want to simultaneously publish on it. And this node is not the only one doing that. In the subscriber, I want to filter out messages which are generated by my node.

Is there any API/package to do that?

In C++, I can imagine publishing/subscribing shared pointers, remembering a few last published messages, and comparing the memory address of the received message with the remembered addresses.

In Python, this is obviously not possible. Or is it?

If the messages have Header fields in them, it might be possible to filter them based on timestamp. Unfortunately, my messages do not have a header, and I can't alter the message definition.

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answered 2016-04-11 10:52:46 -0600

lucasw

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updated 2016-04-11 11:07:04 -0600

How about looking at the _connection_header callerid [Publishers and Subscribers] shown in ( http://wiki.ros.org/rospy/Overview/Pu... ) ?

It says 'We do not recommend using callerid information beyond debugging purposes, as it can lead to brittle code in an anonymous publish/subscribe architecture.'- but it seems like you could reliably get the name of your own node- I did a check and rospy.get_name() and callerid do match up when publishing and subscribing to the same topic in the same node.

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Thanks! Exactly what I was looking for.

peci1 ( 2016-04-11 11:15:32 -0600 )edit

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Asked: 2016-04-11 10:24:48 -0600

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Last updated: Apr 11 '16

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rospy publisher and subscriber in the same node, filter out "own" messages