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I would like to create a .launch file to use the command:
roslaunch robot.launch
But, I don't know how to translate the following shell call into a .launchfile:
rosrun rosjava_bootstrap run.py bumperCar
org.lejos.ros.nodes.bumpercar.BumperCarControl __name:=BumperCarControl
Any help?
You'll want to add an extra args="" parameter to your <node> tag. For more information, take a look at the XML docs for <node>
EDIT: Try something like:
<node pkg="rosjava_bootstrap" type="run.py" args="bumperCar org.lejos.ros.nodes.bumpercar.BumperCarControl" name="BumperCarControl" />
I get the message "Can't locate 'run.py' in 'rosjava_bootstrap' ". I can launch it fine when I use ./build/install/bin/test theTest
I was creating some robot.launch but I didn't have success:
<launch>
<node pkg="rosjava_bootstrap" type="run.py" name="rosjava_bootstrap" output="screen" />
<node pkg="bumperCar" type="BumperCarControl" name="BumperCarControl" output="screen" respawn="true">
<param name="__name" value="BumperCarControl"/>
</node>
</launch>
Can you help me?
If I execute the command:
rosrun rosjava_bootstrap run.py
I receive the following output:
This python script runs rosjava based jars and bootstraps the classpath for the node by looking at its package manifest.
rosrun rosjava_bootstrap run.py <pkg> <node_class> [args ... ]
I suppose that it is necessary in the file robot.launch
Asked: 2012-01-07 01:41:08 -0600
Seen: 859 times
Last updated: Jan 08 '12
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