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Converting ros::Time to plain data structure

kinetic

asked 2019-01-24 09:45:48 -0600

debonair
17 ●12 ●14 ●17

updated 2019-01-24 10:10:18 -0600

ros::time is derived from Time and Time class has 2 members uint32 sec, nsec. If I have ros::time, how do I store it into plain structure where i just have 2 uint32 fields. ros::time has toSec() and toNSec(), but neither of which returns uint32. How do I convert ros::time to

Message time {
  uint32 sec, nsec;
}

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answered 2019-01-24 10:10:50 -0600

VictorLamoine

1495 ●35 ●57 ●69

sec and nsec are public members of the ros::Time class:

  struct Time {
    uint32_t sec;
    uint32_t nsec;
  };

  Time t2;
  ros::Time t1;
  t2.sec = t1.sec;
  t2.nsec = t1.nsec;

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Asked: 2019-01-24 09:45:48 -0600

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Last updated: Jan 24 '19

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Converting ros::Time to plain data structure