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About listener.cpp tutorial. disobey cpp grammar?

asked 2017-02-20 18:25:17 -0500

Bill5785 gravatar image
 #include "ros/ros.h"
#include "std_msgs/String.h"

void chatterCallback(const std_msgs::String::ConstPtr& msg)
  ROS_INFO("I heard: [%s]", msg->data.c_str());

    int main(int argc, char **argv)
      ros::init(argc, argv, "listener");

      ros::NodeHandle n;

      ros::Subscriber sub = n.subscribe("chatter", 1000, chatterCallback);


      return 0;

there is no actual parameter passing to chatterCallback function?

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answered 2017-02-20 21:08:12 -0500

ahendrix gravatar image

chatterCallback is used a function pointer in this context, so the function isn't being called by advertise(). Instead, the address of the function is stored and used later to call that function every time a new message arrives.

Here's a wikipedia article about function pointers and another article specifically about using function pointers in C++ if you want to learn more about the details.

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Thanks! I found I was stupid and forgot the function pointers...

Bill5785 gravatar image Bill5785  ( 2017-02-20 21:29:40 -0500 )edit

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Asked: 2017-02-20 18:25:17 -0500

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Last updated: Feb 20 '17