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position and orientation of the vector

asked 2012-08-21 14:39:30 -0500

Astronaut gravatar image

updated 2012-08-22 09:52:29 -0500

Hello

I went through tf tutorial and some questions here http://answers.ros.org/question/39250/getting-the-position-and-the-pose-of-robot-using-tf_listener/) . I assume that my robot is an rectangle so want to know the position of each 4 vectors of my rectangle.

In my code to get the distance between the fixed point in the map and the center of the robot, center of the base link ( which is the centar of that rectangle I did not used a pose. I used this code. And think is ok.

while (node.ok()){
    tf::StampedTransform transform;
    try{
      listener.lookupTransform("/base_link", "/door1",  
                               ros::Time(0), transform);
    }
    catch (tf::TransformException ex){
      ROS_ERROR("%s",ex.what());
    }

    double x = transform.getOrigin().x();
    double y = transform.getOrigin().y();
    double dist = sqrt(x*x + y*y);

So , but I need to calculate the distance between the 4 vectors (which are formed by the 4 corner points of the rectangle) to that fixed point. So how to get that vectors fist, with the help of my previous code and than the distance.

Thanks.

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answered 2012-08-22 09:51:56 -0500

updated 2012-08-23 06:05:15 -0500

The best way to solve your problem is to use the transformation directly itself. You know the transformation between base_link and door1 in your code, so you can specify the points in the base_link and transform them into the door1 coordinate frame (untested code below)

EDIT: Didn't realize you needed just the distances. Distances can be computed in either frame of reference. In the example below we'll use the door1 frame of reference.

tf::StampedTransform transform; 
try { 
  listener.lookupTransform("/base_link", "/door1", ros::Time(0), transform); 
} catch (tf::TransformException ex){ 
  ROS_ERROR("%s",ex.what()); 
}

tf::Vector3 pt1(robot_length/2, robot_breadth/2, 0);
tf::Vector3 pt2(robot_length/2, -robot_breadth/2, 0);
tf::Vector3 pt3(-robot_length/2, -robot_breadth/2, 0);
tf::Vector3 pt4(-robot_length/2, robot_breadth/2, 0);

tf::Transform tf_base_link_to_door = transform.Inverse();

tf::Vector3 door1_pt(0, 0, 0);
tf::Vector3 required_pt1 = tf_base_link_to_door * pt1;
float dist_pt1 = required_pt1.distance(door1_pt);
tf::Vector3 required_pt2 = tf_base_link_to_door * pt2;
float dist_pt2 = required_pt2.distance(door1_pt);
tf::Vector3 required_pt3 = tf_base_link_to_door * pt3;
float dist_pt3 = required_pt3.distance(door1_pt);
tf::Vector3 required_pt4 = tf_base_link_to_door * pt4;
float dist_pt4 = required_pt4.distance(door1_pt);
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Comments

Sorry but where you calculate the distance here???

Astronaut gravatar imageAstronaut ( 2012-08-22 16:23:11 -0500 )edit

@Astronaut: see updated answer

piyushk gravatar imagepiyushk ( 2012-08-23 06:05:54 -0500 )edit

Yes, I need the distances between the four vectors( create from the 4 corners of the rectangle) and the fixed object(door) in the map. So in this case the four distances are dist_pt1, dist_pt2, dist_pt3 and dist_pt4, wright??

Astronaut gravatar imageAstronaut ( 2012-08-23 14:40:24 -0500 )edit

But dont understand. The door has fixed coordinate in the map frame, for example (1,1,0). So what means here tf::Vector3 door1_pt(0, 0, 0); ??? float dist_pt1..4 gives me the distance between that door in the map and the robot (robot is moving in the map). Yes?

Astronaut gravatar imageAstronaut ( 2012-08-23 15:12:59 -0500 )edit

@Astronaut: The transform from base link to door converts all points to a frame of reference that originates at door1, hence I've used 0,0,0 in the code above. And yes, the distance calculated should be what you need. I recommend reading a bit more about tf at http://www.ros.org/wiki/tf

piyushk gravatar imagepiyushk ( 2012-08-23 18:20:24 -0500 )edit

Ok. Understand But need the distance between the line segment (formed by the 4 corners of the recatngle ) and the door. So that distances are dist_pt1, dist_pt2, dist_pt3 and dist_pt4 from the line segment to the door yes??

Astronaut gravatar imageAstronaut ( 2012-08-23 18:44:06 -0500 )edit

@Astronaut: The distances are to the 4 corner that make up the robot, if that is what you mean by line segments.

piyushk gravatar imagepiyushk ( 2012-08-24 06:45:09 -0500 )edit

I mean i need the distance between the door( a fixed frame in the map) and the 4 line segments (made by the 4 corners of the robot). So i have to know all those 4 distances and find the minimum between all 4 . Understand?

Astronaut gravatar imageAstronaut ( 2012-08-24 14:27:04 -0500 )edit

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Asked: 2012-08-21 14:39:30 -0500

Seen: 1,559 times

Last updated: Aug 23 '12