How to calculate odometry give two poses?

asked 2020-03-31 19:15:14 -0500

RoboStar gravatar image

So I have the pose at times t - 1 and time t. We are given: that the the new pose, at time t, is

x_{t - 1} = [0,0,pi/6] x_{t} = [0.2,0.1,(11*pi)/60]

In my head, I have the two poses. I just need to calculate the difference of the two and that'll be odometry, right? So, subtracting the two vectors: [0.2,0.1,(11*pi)/60] - [0,0,pi/6] = [.2, .1, pi/60]

However, according to the answer checker that doesn't seem to be the right approach. Can someone suggest a strategy to go about this? Any help is very much appreciated.

edit retag flag offensive close merge delete