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What is the meaning of "scale 0.25 meters"?
The picture has been generated with package fiducial in object_recognition stack. See function PoseDrawer in fiducial.cpp. What came to my mind is that the vectors representing the three axes are of length 0.25m. But alas that's just a guess.
Yes, you are correct. From the code:
414 void PoseDrawer(cv::Mat& drawImage, const cv::Mat& K, const PoseRT& pose)
415 {
416 Point3f z(0, 0, 0.25);
417 Point3f x(0.25, 0, 0);
418 Point3f y(0, 0.25, 0);
419 Point3f o(0, 0, 0);
The length of the drawn arrows is 0.25 meters for scale.
Asked: 2011-04-21 00:34:35 -0500
Seen: 449 times
Last updated: Sep 02 '11
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