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how to change robot's movemetns directions in the odometry frame

asked 2019-06-08 21:15:01 -0500

ShehabAldeen gravatar image

updated 2019-06-08 21:16:56 -0500

Hello,

I am trying to use the navigation stack into my project to add autonomous navigation capability to my robot.

the xyz axis of my sensor is fixed in an orientation different than the odometry frame. the following pic shows both the odom frame and the base_footprint frame, what I want basically that if I moved in y axis of the base_footprint frame then I am moving forward according to the odom frame since the y axis of my sensor is facing forward on my robot.

image description

I am using the following code to publish the odometry data over ROS

#!/usr/bin/env python

import math
from math import sin, cos, pi
import rospy
import tf
from nav_msgs.msg import Odometry
from sensor_msgs.msg import Imu
from geometry_msgs.msg import Point, Pose, Quaternion, Twist, Vector3

class odometry_publisher(object):

    def __init__(self):
        self.odom_pub = rospy.Publisher("odom", Odometry, queue_size=50)
        self.odom_broadcaster = tf.TransformBroadcaster()
        self.map_broadcaster = tf.TransformBroadcaster()
        self.sub = rospy.Subscriber("/camera/odom/sample", Odometry, self.callback, queue_size=10)
        self.x = 0.0
        self.y = 0.0
        self.th = 0.0
        self.w = 0.0
        self.vx = 0.0
        self.vy = 0.0
        self.vth = 0.0
        self.qx = 0.0
        self.qy = 0.0
        self.current_time = rospy.Time.now()
        self.last_time = rospy.Time.now()

        self.r = rospy.Rate(100.0)


    def callback(self,msg):
        self.x = msg.pose.pose.position.x
        self.y = msg.pose.pose.position.y
        self.z = msg.pose.pose.position.z
        self.vx = msg.twist.twist.linear.x
        self.vy = msg.twist.twist.linear.y
        self.vth = msg.twist.twist.angular.z
        self.th = msg.pose.pose.orientation.z
        self.w = msg.pose.pose.orientation.w
        self.qx = msg.pose.pose.orientation.x
        self.qy = msg.pose.pose.orientation.y

    def publish(self):
        while not rospy.is_shutdown():
            self.current_time = rospy.Time.now()

            # first, we'll publish the transform over tf
            self.odom_broadcaster.sendTransform(
                (self.x, self.y, 0.),
                (self.qx,self.qy,self.th,self.w),
                self.current_time,
                "base_footprint",
                "odom"
            )

            # next, we'll publish the odometry message over ROS
            odom = Odometry()
            odom.header.stamp = self.current_time
            odom.header.frame_id = "odom"

            # set the position
            odom.pose.pose = Pose(Point(self.x, self.y, 0.), Quaternion(self.qx,self.qy,self.th,self.w))

            # set the velocity
            odom.child_frame_id = "base_footprint"
            odom.twist.twist = Twist(Vector3(self.vx, self.vy, 0), Vector3(0, 0, self.vth))

            # publish the message
            self.odom_pub.publish(odom)
            self.r.sleep()

if __name__ == '__main__':

    rospy.init_node('odometry_publisher')
    object__ = odometry_publisher()
    object__.publish()
    rospy.spin()
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1 Answer

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answered 2019-06-08 23:00:22 -0500

billy gravatar image

You should not try to mess with the orientation of the baselink because the sensor is rotated. Change the transform between the sensor and the baselink to account for that.

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Comments

do you suggest to do that with a static transfrom publisher? or what is the best way to do it?

ShehabAldeen gravatar image ShehabAldeen  ( 2019-06-09 15:14:28 -0500 )edit

You must already have a TF from sensor to base, so you need to figure out how to change that TF to account for the rotation. If you provide more info about it it would be easier to help.

billy gravatar image billy  ( 2019-06-09 20:09:18 -0500 )edit

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Asked: 2019-06-08 21:15:01 -0500

Seen: 1,428 times

Last updated: Jun 08 '19