Problem with MoveGroupInterface::getRobotModel() providing only const version [closed]

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I'm trying to get my own instance of JointModelGroup from code equivalent to this:

auto move_group = moveit::planning_interface::MoveGroupInterface {"panda_arm"};
auto robot_model_constptr = move_group.getRobotModel();
auto joint_model_group = std::unique_ptr<moveit::core::JointModelGroup> {robot_model_constptr->getJointModelGroup("panda_arm")};

However this doesn't compile (long error omitted for brevity):

error: no matching function for call to ‘std::unique_ptr<moveit::core::JointModelGroup>::unique_ptr(<brace-enclosed initializer list>)’
   auto joint_model_group = std::unique_ptr<moveit::core::JointModelGroup> {robot_model_constptr->getJointModelGroup("panda_arm")};

which ultimately boils down to

error: invalid conversion from ‘const moveit::core::JointModelGroup*’ to ‘std::unique_ptr<moveit::core::JointModelGroup>::pointer {aka moveit::core::JointModelGroup*}’ [-fpermissive]
   auto joint_model_group = std::unique_ptr<moveit::core::JointModelGroup> {robot_model_constptr->getJointModelGroup("panda_arm")};

This stems apparently from getRobotModel either being a const function or returning a ConstPtr (likely the first), as that leads to calling the const version of getJointModelGroup (instead of the existing non-const) which makes it impossible to get the unique_ptr.

I have found however that this does compile:

auto move_group = moveit::planning_interface::MoveGroupInterface {"panda_arm"};
auto robot_model_constptr = move_group.getRobotModel();
auto robot_model = * robot_model_constptr;
auto joint_model_group = std::unique_ptr<moveit::core::JointModelGroup> {robot_model.getJointModelGroup("panda_arm")};

and I'm therefore left wondering if I'm doing something I shouldn't or if there is a better way to get joint_model_group without declaring things I don't necessarily need myself.

EDIT: from what I can gather e.g. here I get the const version of getJointModelGroup because getRobotModel is const, is what I'm trying to say.