Changing a variable inside a running node

asked 2018-05-24 18:23:01 -0500

inani47
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updated 2018-05-24 20:40:10 -0500

I'm trying to change a variable that sets the speed of a robot after it has been initialized with a specific value, say 0.5. After some time passes, I require to change the value to, say 1. How can I accomplish this?

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This sounds a bit like an XY Problem. Can you rephrase what you want to do without describing how you want to do it (ie, without describing it in terms of a service)

ahendrix ( 2018-05-24 20:33:06 -0500 )edit

@ahendrix done

inani47 ( 2018-05-24 20:39:32 -0500 )edit

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answered 2018-05-24 21:16:24 -0500

ahendrix

47576 ●179 ●367 ●662 http://namniart.com/

Most robots use topics for sending periodic or continuous commands to motors and actuators.

The tutorial gives a good overview of topics: http://wiki.ros.org/ROS/Tutorials/Und...

And this turtlesim tutorial gives a more in-depth look at how to use topics to control a robot (or simulator): http://wiki.ros.org/turtlesim/Tutoria...

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I considered this.. But I have the same node running with two different names.. And i need to change the variable for each node differently

inani47 ( 2018-05-24 21:26:53 -0500 )edit

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If you have two copies of the same node running, I suggest you remap the service or topic names used by each copy of that node so that each copy of the node has it's own service and topic names.

ahendrix ( 2018-05-24 21:43:29 -0500 )edit

@ahendrix will launching nodes with different namespaces also achieve this?

inani47 ( 2018-05-30 17:57:45 -0500 )edit

Yes; namespaces will typically do this too (unless the node uses absolute topic names, but that's unusual).

ahendrix ( 2018-05-30 18:05:58 -0500 )edit

By the way, I was able to implement this using a service, I just felt it was a cleaner way to do things. Just personal preference. So I guess what I was really asking is will there be two sets of services created if I launch with different namespaces?

inani47 ( 2018-05-30 18:13:45 -0500 )edit

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Yes; namespacing applies to services in the same way.

ahendrix ( 2018-05-30 18:20:44 -0500 )edit

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answered 2018-05-24 20:51:04 -0500