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Hi
Is there a way to resolve the current pkg folder name related to a launch file? My launch files uses the
$(find current_pkg)/my_file.xy
substitution to find and resolve a file in my current package. Every time I am renaming my pkg or if have to check all the finds. Is there a more common way such as
$(CURRENT_PKG)/my_file.xy
Greetings Markus
If you can set a system-wide environment variable for CURRENT_PKG (might need to put it in ~/.bashrc file), you can swap the $(find current_pkg) part with $(env CURRENT_PKG).
@Markus Bader: posting comments on an answered question from 2016 is not the most visible way to ask for updates.
I happened to notice as I'm watching this question, but without that, your comment would be almost invisible.
Perhaps the dirname substitution argument can do what you are looking for:
$(dirname)returns the absolute path to the directory of the launch file in which it appears. This can be used in conjunction withevalandif/unlessto modify behaviour based on the installation path, or simply as a convenience for referencinglaunchoryamlfiles relative to the current file rather than relative to a package root (as with$(find PKG)). For example:<include file="$(dirname)/other.launch" />Will expect to find
other.launchin the same directory as the launch file which it appears in.
This does not make it relative to the package, but relative to the .launch file in which this substitution is used.
Asked: 2016-08-19 08:24:22 -0500
Seen: 556 times
Last updated: Nov 10 '20
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Is there anything new on this?