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This seems to be correct. The translation is not the same because there is a slight rotation in this transform. In that case, the translation does not need to be negative of the inverse transform. For a visual explanation, consider the following picture:

When expressing the location of frame_1 in the coordinates of frame_0 and vice versa, you can see that the norm will be the same, but the direction of the vector won't be. (In this case, the T vector of frame_0 expressed in frame_1 will be almost aligned with the -X1 axis, as opposed to the direction of the negative of the drawn T vector.)

Hope that helps.