[Ros2] load a .yaml file in cpp program

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In ROS2, Is there a way to load a .yaml file in cpp program to set the parameters into node.

Currentlly (in ROS2) we can load .yaml file either commandLine i.e. ros2 run pkg_name nodename __params:=:<path>/test.yaml Or through python launch pkg as below.

yaml file test.yaml:

nodename:
  ros__parameters:
    name: aaa
    type: bbb
    params:
      param1: 10.0
      param2: xyz

.launch.py file test.launch.py:

def generate_launch_description():
    parameters_file_dir = pathlib.Path(__file__).resolve().parent
    parameters_file_path = parameters_file_dir / 'test.yaml'
    os.environ['FILE_PATH'] = str(parameters_file_dir)

    test_node = launch_ros.actions.Node(
            package='pkg_name', node_executable='file_executable_name', node_name='nodename,
            output='screen',
            parameters=[
                parameters_file_path,
                str(parameters_file_path),
                [EnvironmentVariable(name='FILE_PATH'), os.sep, 'test.yaml'],
            ],
        )

    return LaunchDescription([
        test_node,
        launch.actions.RegisterEventHandler(
            event_handler=launch.event_handlers.OnProcessExit(
                target_action=test_node,
                on_exit=[launch.actions.EmitEvent(event=launch.events.Shutdown())],
            )),
])

I am looking similar way to load .yaml in cpp program to get/set perameters in a particular node?